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If I have 21 liters of gas held at a pressure of 78 atm and a temperature of 900 K, what will
be the volume of the gas if I decrease the pressure to 45 atm and decrease the
temperature to 750 K?

Respuesta :

oladipupog80

Answer:

30.33L

Explanation:

Using Boyle's law which states that the volume of a given mass of gas is inversely proportional to the pressure, provided temperature remains constant  and Charles law states that the volume of a given mass of gas is directly proportional to the temperature provided the pressure remains constant

P1V1/T1 = P2V2/ T2

P1 =  78atm, V1 = 21L , T1 = 900K

P2 = 45atm, V2 = ? , T2 =750K

78Ă— 21 / 900 = 45Ă—V2 / 750

1638/900 = 45 V2 / 750

1638Ă—750 = 900Ă—45V2

1228500 = 40500V2

Divide both sides by 40500

1228500Ă·40500= V2

V2 = 30.33L

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