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02-08-2022
Mathematics

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Find the cube root of 1+¡^5

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bunnuika bunnuika

02-08-2022

¡^5= ¡
so we have cuberoot of 1+¡
x=1 y=1
to find d modulus we have
r=squaroot of 1²+ 1²= 2
r= squaroot of 2
we find the argard diagram by using
tan(tha)=y/x
tan(tha)=1/1
tha=tan-¹ 1
tha=45
using the formula of root of complex number we have
z=r^1/n (cos(tha+2k(180))/n +¡sin(tha+2k(180)/n) when k elemen z+ and n=3
when k=0
we have
z=(squaroot of 2)^1/3 *1/2squaroot of 2
like wise when k=1 and k=2

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