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Hal has 20 pieces of candy in a bag: 12 mint sticks, 5 jelly treats, and 3 fruit tart chews. If he eats one piece every 8 minutes, what is the probability his first two pieces will both be mint sticks?

Respuesta :

MohammadHaisam
Use the AND operation so 12/20 x 11/19 total candies will be reduced to 19 for 2nd mint bcz he is not replacing them if first was mint then chances of second being mint is 11 so 132/380 which can be further simplified
JeanaShupp

Answer: [tex]\dfrac{33}{95}[/tex]

Step-by-step explanation:

Given : Number of pieces of candy in the bag =20

Number of pieces of mint sticks =12

If he eats one piece every 8 minutes, then the number of ways that he eats mint sticks =[tex]12\times11=132[/tex]

The total number of ways that he eats any two pieces of candies=[tex]20\times19=380[/tex]

Now, the probability his first two pieces will both be mint sticks :-

[tex]\dfrac{132}{380}=\dfrac{33}{95}[/tex]

Hence, the probability his first two pieces will both be mint sticks =  [tex]\dfrac{33}{95}[/tex]